# Using the Finance Menu of the TI-83/84/Plus calculators KEY

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1 Using the Finance Menu of the TI-83/84/Plus calculators KEY To get to the FINANCE menu On the TI-83 press 2 nd x -1 On the TI-83, TI-83 Plus, TI-84, or TI-84 Plus press APPS and then select 1:FINANCE The FINANCE menu looks like this: TVM represents Time, Value, Money We will use option 1:TVM Solver The TVM Solver menu looks like this: You may not see these numbers above. If this is the first time that you have used this menu then all of the entries will be displayed as 0. When solving an exercise, fill out all of the other entries first and then go back onto the entry you want to Solve. Once you are on that entry, press ALPHA Enter (Solve). For Systematic Savings FV = total deposits + interest For Systematic Loans total payments = original loan amount + interest 1

3 1. Suppose you deposit \$200 at the end of each month into an account earning 5.4% interest compounded monthly. How much will be in the account after making deposits for 15 years? N = 12*15 = 180 total monthly deposits I% = 5.4 PMT = -200 FV = ALPHA SOLVE The parents of a kindergarten student want to save \$200,000 to pay for the estimated cost of her college education. They plan to invest in a mutual fund that earns about 8% compounded quarterly. How much should the parents deposit at the end of each quarter so the account will be worth \$200,000 in 13 years? N = 4*13 = 52 total quarterly deposits I% = 8 PMT = ALPHA SOLVE FV = P/Y = 4 C/Y = 4 There will be \$55, in the account after making deposits for 15 years. The parents should deposit \$ at the end of each quarter. 3. Suppose you want to have \$3000 available for the down payment on a car. If you deposit \$120 at the end of every month into an account earning 6% compounded monthly, how long will it take until you have the down payment? N = = ALPHA SOLVE I% = 6 PMT = -120 FV = total monthly deposits = nt = 12t = t It will take approximately 1.97 years to have the down payment. 4. On January 24, 2012, the United States average interest rate for money market accounts was 0.51%, whereas one of the best rates in the country, 0.90%, was being offered by First Internet Bank of Indiana. If \$100 is invested at the end of each month into an account, how long will it take the account to grow to \$10,000 if it is invested at 0.90% compounded monthly? N = ALPHA SOLVE I% = 0.90 PMT = -100 FV = total monthly deposits = nt = 12t = t It will take approximately 8.04 years to grow to \$10,000 if invested at 0.90% compounded monthly. 3

4 5. Suppose a 27-year-old man bought an annuity (a systematic savings plan) through the Jackson National Life Insurance Company in The plan calls for deposits of \$100 at the end of each month and pays an interest rate of 6.25% compounded monthly. a. How much will the annuity be worth when the man is 65-years-old in 2035? t = = 38 years Also, t = = 38 years N = 12*38 = 456 total monthly deposits I% = 6.25 PMT = -100 FV = ALPHA SOLVE The annuity will be worth \$185, when the man is 65-years-old in b. How much of the future value will be from deposits? 456 total monthly deposits times \$100 per deposit = 456*100 = 45,600 \$45,600 of the future value is from total deposits. c. How much of the future value will be from interest? For Systematic Savings we have: Future Value total from deposits = interest \$185, \$45,600 = interest \$185, \$ 45, \$140, \$140, of the future value is from interest. 4

5 6. After finishing your college degree you start a job that has a retirement plan. Suppose that \$100 is deposited monthly into your retirement account which earns interest compounded monthly at a 6% annual rate. a. How much money will be in the retirement account after 30 years? How much would you have paid in total deposits? N = 12*30 =360 total monthly deposits I% = 6 PMT = -100 FV = ALPHA SOLVE \$100, will be in the retirement account after 30 years. 360 total monthly deposits times \$100 per deposit = 360*100 = 36,000 The total amount from deposits is \$36,000. b. If instead of starting the retirement plan when you are hired, you wait until 10 years before retirement to start making the deposits. To help compensate for the delay, you make your monthly deposits \$300. In this case, how much money will be in the account when you retire? (Assume the same interest rate). How much would you have paid in total deposits? N = 12*10 = 120 total monthly deposits I% = 6 PMT = -300 FV = ALPHA SOLVE \$49, will be in the retirement account after 10 years. 120 total monthly deposits times \$300 per deposit = 120*300 = 36,000 The total amount from deposits is \$36,000. 5

6 7. Suppose you want to purchase a car and the added charges for taxes, title, license, and fees bring the total to \$16, You must make a 10% down payment and pay for the remainder through a car loan at an interest rate of 7.9% compounded monthly. You are to repay the loan with monthly payments for 4 years. a. What are the monthly payments? The down payment will be \$16,032.31*0.10 = \$1, So that \$16, \$ 1, \$14, is left to pay with a loan N = 12*4 = 48 total monthly payments I% = 7.9 PV = PMT = ALPHA SOLVE The monthly payments will be \$ b. What is the total amount you make in payments over the life of the loan? 48 total monthly payments times \$ per payment = 48* = \$16, The total amount made in payments is \$16, c. How much interest will you pay over the life of the loan? For Systematic Loans we have: total amount in payments original loan amount = interest \$16, \$14, = interest \$16, \$14, \$ 2, The total amount paid in interest is \$2,

7 8. To pay for his home, Dr. Carrera has a mortgage (home loan) of \$300,000 at 6.6% annual interest rate compounded monthly with a monthly payment plan over 30 years. a. How much would the scheduled payments on the loan be? N = 12*30 =360 total monthly payments I% = 6.6 PV = PMT = ALPHA SOLVE The monthly payments would be \$1, b. If Dr. Carrera pays \$100 extra each month, how long will it take him to pay off the loan? N = ALPHA SOLVE I% = 6.6 PV = PMT = total monthly payments = nt = 12t = t It will take approximately years for Dr. Carrera to pay off the loan. c. How much does Dr. Carrera save in payments over the life of the loan by paying \$100 extra each month? The total amount Dr. Carrera pays in part (a) is 360*1, = \$689, The total amount Dr. Carrera pays in part (b) is *2, = \$627, \$689, \$627, \$ 62, The total amount Dr. Carrera saves by paying an extra \$100 extra each month is \$62,

8 9. Susan s friend Amber has fallen on hard times and needs to borrow some money. Looking at her weekly paycheck, Amber decides that she can afford to give Susan \$20 a week to pay her back. Amber promises Susan that she will pay her back on a weekly basis, with interest, over a period of 6 months. They agree on a 10% annual interest rate compounded weekly. How much can Amber afford to borrow? N = 52*(6/12) = 26 weekly payments I% = 10 PV = ALPHA SOLVE PMT = -20 P/Y = 52 C/Y = Chad Porter takes out a \$150,000 loan for a new house at an interest rate of 4.5% per year compounded monthly and the loan is to be paid back monthly for 30 years. Thirteen years and 4 months later Chad wins the lottery and wants to pay off the remaining balance on his loan. How much will Chad have to pay at that time? First we must solve for the amount of the monthly payments. N = 12*30= 360 monthly payments I% = 4.5 PV = PMT = ALPHA SOLVE Under such a payment plan, Amber can afford to borrow \$ The monthly payments will be \$ Now, given this payment plan, we must solve for the balance of the loan (FV) after thirteen years and 4 months of payments. NOTE: There are two ways to figure out the value of N at this time. Way #1 t is the total time in years so t = (13 + 4/12) years. Therefore N= nt = 12(13 + 4/12) = 160 Way # 2 N is the total monthly payments, so we have N = 12*13 monthly payments + 4 monthly payments = 160 monthly payments N = 160 monthly payments I% = 4.5 PV = PMT = (This value is just left over from the previous solving) FV = ALPHA SOLVE Of the original \$150,000 borrowed, Chad would still owe \$106, after thirteen years and 4 months of payments. (\$106, also accepted if using PMT = ) By paying off the loan early, Chad does not have to make any future payments of \$ from the original payment plan, and therefore saves paying interest taken out from all of those future payments. 8

9 Additional Exercises 11. Suppose a couple takes out a 15-year mortgage for \$130,000 at 2.75% interest rate compounded quarterly. After 10 years of quarterly payments, they inherit a small fortune from the passing of their rich uncle and decide to pay off the loan. How much will they have to pay? First we must solve for the amount of the quarterly payments. N = 4*15 = 60 quarterly payments I% = 2.75 PV = PMT = ALPHA SOLVE P/Y = 4 C/Y = 4 Now, given this payment plan, we must solve for the balance of the loan (FV) after ten years of payments. N = 4*10 = 40 quarterly payments I% = 2.75 PV = PMT = (This value is just left over from the previous solving) FV = ALPHA SOLVE P/Y = 4 C/Y = 4 By paying off the loan early, the couple does not have to make any future payments of \$2, from the original payment plan, and therefore saves paying interest taken out from all of those future payments. 12. When Stephanie was born, her grandparents deposited \$1500 in an account paying 5.75% interest compounded semi-annually. How much money was in the account when Stephanie turned 18 and was ready for college? Here Stephanie s grandparents are making a one-time (lump sum) deposit so this situation is not systematic deposits. But it is compounded so we have = = The quarterly payments will be \$2, Of the original \$130,000 borrowed, the couple would still owe \$49, after ten years of payments. (\$ also accepted if using PMT = ) When Stephanie turned 18 and was ready for college, \$4, was in the account. 9

10 13. Chris decides that he wants to save up money for a new canoe. After doing some online research he figures that the total amount the canoe would cost plus taxes, and other fees should be about \$900 to \$1000. He finds a savings account that will provide him a fixed 4% annual interest rate, compounded monthly. How much should he put into the account at the end of each month if he wants to have \$1000 in 2 years? N = 12*2 = 24 total monthly deposits I% = 4 PMT = ALPHA SOLVE FV = If a total of \$1420 is due after 4 years on a simple interest loan for \$1200, what interest rate is being charged? For simple we have = = = = = The simple interest rate that is being charged is 4.58%. Chris should deposit \$40.09 at the end of each month. 15. You need to purchase a vehicle to get back and forth to school and work. You find a 1-year old, pre-owned vehicle in terrific condition for \$9845. The salesman offers you the vehicle for \$800 down and \$195 per month for 4 years. a. How much will you be borrowing? \$9845 \$800=\$9045 You will be borrowing \$9045. b. What interest rate are you being charged if interest is compounded monthly? N = 12*4 = 48 total monthly payments I% = ALPHA SOLVE You will be charged an PV = 9045 PMT = -195 interest rate of about 1.69% if interest is compounded monthly. c. How much interest will you pay over the life of the loan? 48 total monthly payments times \$195 per payment = 48*195 = \$9,360 total amount in payments. For Systematic Loans we have: total amount in payments original loan amount = interest \$9,360 \$9,045 = interest \$9,360 \$9,045 \$ 315 The total amount paid in interest is \$

11 16. Suppose that \$1000 is put into an account with 8% annual interest compounded monthly for 15 years. What interest rate would give the same amount of money after 15 years if the simple interest method is used? For compounded without systematic deposits we have = = =\$ Then for simple we have = = = = = = The simple interest rate that would give the same amount of money is about 15.38%. Savings Activity: Suppose you deposit \$50 per month into an account earning 5% per year compounded monthly. You want to know how much you will have at age 60 if you start the savings plan at various ages. Also calculate how much of the final value is from the deposits and how much is interest earned. Starting Age Years until 60 Final Value Total \$ deposited Interest earned \$76, \$24,000 \$52, \$41, \$18,000 \$23, \$20, \$12,000 \$8, \$7, \$6,000 \$1,

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