# Chapter 5. Rational Expressions

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1 5.. Simplify Rational Expressions KYOTE Standards: CR ; CA 7 Chapter 5. Rational Expressions Definition. A rational expression is the quotient P Q of two polynomials P and Q in one or more variables, where Q 0. Some examples of rational expressions are: x x 2 + 2x 4 ab 2 c 4 x y x 2 +y 2 Rational expressions in algebra are closely related to rational numbers in arithmetic as their names and definitions suggest. Recall that a rational number is the quotient p of two integers p and q, where q 0, as stated in Section.. The procedure q used to simplify a rational expression by dividing out the greatest common factor of the numerator and denominator is the same as the procedure used to reduce a rational number (a fraction) to lowest terms. The procedures used to multiply, divide, add and subtract rational expressions are the same as the corresponding procedures used to multiply, divide, add and subtract rational numbers. Example. Find the greatest common factor (GCF) of the numerator and the denominator of each rational expression. Write the expression by factoring out the GCF in both the numerator and the denominator. Then divide out the GCF to write the rational expression in simplified form. (a) 8a2 b 5 c 2a 4 b (b) 9x2 (2x ) 24x 5 (2x ) Solution. (a) The GCF of the numerator and denominator of 8a2 b 5 c 2a 4 b is 6a2 b. We factor out the GCF of the numerator and denominator and divide it out to obtain 8a 2 b 5 c 2a 4 b 6a2 b b 4 c Factor 6a 2 b from numerator and 6a 2 b 2a 2 denominator b4 c Divide out (cancel) 6a 2 b 2a 2 98

2 (b) The GCF of the numerator and denominator of 9x2 (2x ) 24x 5 (2x ) is x 2 (2x ). We factor out the GCF of the numerator and denominator and divide it out to obtain 9x 2 (2x ) 24x 5 (2x ) x 2 (2x ) (2x ) 2 x 2 (2x ) 8x Factor x 2 (2x ) from numerator and denominator (2x )2 8x Divide out (cancel) x 2 (2x ) Example 2. Simplify the given rational expression. a 2 b x 2 x 6 (a) (b) (c) a2 b a 2 b (d) y2 x 2 a 2 b+ 6ab x 2 + 5x 2 a 2 b+a 2 x 2 xy a 2 b Solution. (a) We factor the denominator of and divide out the a 2 b+ 6ab GCF ab of numerator and denominator to obtain a 2 b a 2 b+ 6ab a 2 b ab(a+2) a a+ 2 Factor ab from numerator and denominator Divide out (cancel) ab Note: Remember that you can only divide out, or cancel, an expression if it is a factor of the numerator and denominator of a rational expression. A common mistake in this case is to assume that a 2 bis a factor of the denominator instead of a term and cancel it out to obtain the incorrect simplification 6ab. (b) We employ what we have learned about factoring polynomials to factor x 2 x 6 the numerator and denominator polynomials of and divide out the x 2 + 5x 2 common factor x+2 to obtain x 2 x 6 (x )(x+2) x 2 + 5x 2 (x )(x+ 2) x x Factor numerator and denominator polynomials Divide out (cancel) x+2 99

3 (c) We factor the numerator and denominator polynomials of a2 b a 2 b a 2 b+a 2 in two steps and divide out the common factor after each step to obtain a 2 b a 2 b a 2 b+a 2 a2 (b b) a 2 (b+) Factor a 2 from numerator and denominator polynomials b(b2 ) b+ Divide out (cancel) a 2 ; Factor b b b(b )(b+) b+ Factor b 2 (b )(b+) b(b ) Divide out (cancel) b+ (d) We factor the numerator and denominator polynomials of y2 x 2 x 2 xy steps and divide out the common factor after the second step to obtain in two y 2 x 2 x 2 xy (y x)(y+x) x(x y) (x y)(y+x) x(x y) y+x x Factor numerator and denominator polynomials Write y x (x y) Divide out (cancel) x y Exercise Set 5. Find the greatest common factor (GCF) of the numerator and the denominator of each rational expression. Write the expression by factoring out the GCF in both the numerator and the denominator. Then divide out the GCF to write the rational expression in simplified form.. 45a b 4 9a 5 b. x(x )2 5x 2 (x ) 5. x 2 (x+ ) x 7 (x+ )(2x ) 2. 8a0 b 6a 5 b 4. 24x y 5 0y z (x+) (x ) 48(x+) 5 (2x+ ) 00

4 Simplify the rational expression. 7. 8x 4 y 7 24x 8 y 4 z 8. 6(x+4) (x 2) 2 0(x+4) (a b)(a+b)2 (x 2)(x+ 5) (b a)(a+b) (2 x)(x+ 5). x + x 2 x 2 + 2x 4. a2 b 2 +a 2 b 4 a 2 b 2 +a 4 b 2 2. x2 5x 2x x 2 y x 2 y+x 4 y 2 5. x yz+xy z+xyz x 2 y 2 z t 4 8t 4t 2 2t 7. t 2t 2 +t t 2 t 9. x 2 4 x a2 b 2 0a 6 b 8 2a 2 b x2 + 4x+ x+ 2. x 2 + 6x+8 x 2 + 5x+4 2. x2 + 2x x 2 +x (a )2 a 2 9 6x+2 x 2 + 5x x 2 4 2x 2 +2x y2 y 2 y 2 + 5y y + 4y 8y 2y + 4y 6y 28. 2x2 + 5x x 2 +x x 2 + 2xy+y 2 x 2 + 2xy y 0. 2x2 + 6xy+ 4y 2 2 4x 2 4y 2. 6x+2 4x 2 + 6x 4 2. x 7 + 4x 6 +x 5 x 4 + x + 2x 2 0

5 . x2 +2x+2 9x t 2 t 8 2t 2 + 5t+ 4. t +t 2 t t 4 t 6t 2 2t 2 7t+ 6 02

6 5.2. Multiply and Divide Rational Expressions KYOTE Standards: CR 2; CA 6 The procedures used to multiply and divide rational expressions are the same as those used to multiply and divide fractions. For example, if A, B, C and D are polynomials with B 0 and C 0, then A B C D A C B D and A B C D A B D C A D B C Once these operations are performed, the only remaining task is to simply the resulting rational expression as we did in Section 5.. A few examples should illustrate this process. Example. Perform the multiplication or division of the given rational expressions and simplify. (a) x 2 + 2x 8 x 2 + x x 5 (b) x 2 9 x 2 5x+ 6 5x 0 x2 2x 4 2a 2 ab b 2 + 4ab+b 2 (c) a 2 + 6ab+9b 2 a2 b a Solution. (a) We factor the numerators and denominators of both rational expressions in the product x 2 + 2x 8 x 2 + x and simplify the resulting rational x 2 9 x 2 5x+ 6 expression to obtain x 2 + 2x 8 x 2 + x x 2 9 x 2 5x+ 6 (x 2)(x+4) (x )(x+ ) x(x+ ) (x 2)(x ) Given product of rational expressions Factor polynomials x(x+4) Divide out (cancel) 2 x 2, x+ (x ) (b) We invert the second expression multiply it by the first expression x 5 5x 0 x 2 2x 4 in the quotient x 5 and simplify to obtain 5x 0 x2 2x 4, x 5 5x 0 x2 2x 4 Given quotient of rational expressions 0

7 x 5 5x 0 2x 4 Invert x 2 x 2 2x 4 and multiply x 5 5(x 2) 2(x 2) x 2 Factor 2x 4, 5x 0 2x 5 Divide out (cancel) x 2, x 2 (c) We factor the numerators and denominators of both rational expressions 2a 2 ab b 2 + 4ab+b 2 in the product in two steps and divide out the common a 2 + 6ab+9b 2 a2 b a factor after each step to obtain 2a 2 ab b 2 + 4ab+b 2 a 2 + 6ab+9b 2 a2 b a (2a+b)(a b) (a+b)(a+b) (a+b)(a+b) b a (2a+b)(a b) a+b (a+b) b a (2a+b)(b a) a+b a+ b b a (2a+b)(a+b) a+ b Given product of rational expressions Factor polynomials Divide out (cancel) a+b Write a b (b a) Divide out (cancel) b a Exercise Set 5.2 Perform the multiplication or division and simplify.. x2 4y 2x y 2. y y. 5. x a 2 a+2 6a+2 4. a 2 8a 6 5a+ 20 2a+8 4a 5 y x 2a+ 6. 6a+9 2 y a a 4 7. x (x+ ) x 2 (x+ ) 4x 8. x+2 9x2 + 6x 4x 04

8 9. x 2 x 2 9 x+ 2x. x2 x 6 x 2 x+ x. x 2 y+xy 2 x 2 2xy y 2 x 2 9y 2 5x 2 y 0. 2x2 + 7x 4 2x 2 x+ x x 2. x 2 + 5x+ 6 x 2 + 2x x +x x 2 + 4x+ 4. 2x2 + x+ x 2 + 2x 5 x2 + 6x+ 5 2x 2 7x+ 5. x 4 x+ 2 x x 2 + 4x a2 ab b 2 a 2 2ab+b 2 2a2 +ab b 2 2a 2 + ab+b 2 6. x2 + 2x x 2 x 2 2x+ x 2 7x+2 8. x 2 2x 5 x 2 4x 5 x2 +8x+7 x 2 + 7x+2 05

9 5.. Add and Subtract Rational Expressions KYOTE Standards: CR 2; CA 6 The procedures used to add and subtract rational expressions are the same as those used to add and subtract fractions. Two rational expressions with the same denominator are relatively easy to add and subtract. For example, if A, B and C are polynomials with C 0, then A C +B C A+B C and A C B C A B C The procedure is more difficult to carry out if the denominators are different. For example, suppose A, B, C and D are polynomials with C 0 and D 0. To add the rational expressions A C and B, we must first find a common denominator, CD D in this case. We then find equivalent expressions for A C and B D with this denominator and add to obtain A C +B D AD CD +BC DC AD+BC CD In practice, it is important to find the least common denominator, or LCD, because otherwise the algebra becomes messy and it is difficult to reduce the rational expression that is obtained. In Section.2, we observed that the LCD of two or more fractions is the least common multiple, or LCM, of their denominators. We use this same approach to find the LCD of two or more rational expressions. Example. Suppose the polynomials given are denominators of rational expressions. Find their least common denominator (LCD). (a) 6x y 4, 8x 5 y (b) x 2 9,x 2 2x 5 (c) 5(a+) 2, 6(a+), 0(a+) Solution. (a) To find the LCD of the denominators 6x y 4 and 8x 5 y, we factor 62 and 8 2 into products of powers of prime numbers. We then examine these denominators in factored form: 2 x y 4, 2 x 5 y We view the variables x and y as prime numbers and we take the largest power of each prime factor 2,, x and y in the two expressions to form the LCD as we did in Section.2. The LCD of 6x y 4 and 8x 5 y is therefore 2 x 5 y 4 24x 5 y 4 06

10 (b) To find the LCD of the denominators x 2 9 and x 2 2x 5, we factor them to obtainx 2 9(x )(x+ ) and x 2 2x 5 (x 5)(x+ ). The LCD of x 2 9 and x 2 2x 5 is therefore the product (x )(x+ )(x 5) Note. The product (x )(x+ ) 2 (x 5)is a common denominator but not the least common denominator. (c) To find the LCD of the denominators 5(a+) 2, 6(a+) and 0(a+), we factor 62 4 and 02 5 into products of powers of primes and examine these denominators in factored form: 5(a+) 2, 2 4 (a+), 2 5(a+) We take the largest power of each prime factor 2, 5 and a+, and multiply them together to obtain their LCD 2 4 5(a+) 80(a+) Example 2. Find the LCD of the given pair of rational expressions. Express each rational expression in the pair as an equivalent rational expression with the LCD as its denominator. (a) 4a 2 b, 5 6ab (b) x x 2 x 2, x+4 x 2 + x 0 Solution. (a) The LCD of the denominators 4a 2 b and 6ab is 2a 2 b. Thus 2a 2 b is a multiple of both 4a 2 b and 6ab, and we can write 2a 2 b 4a 2 b b 2 2a 2 b 6ab 2a We can then write 4a 2 b and 5 as equivalent rational expressions with the same 6ab denominator 2a 2 b. 4a 2 b b2 4a 2 b b 9b a 2 2a 2 b 6ab 6ab 2a 0a 2a 2 b (b) We must factor the denominator polynomials x 2 x 2(x 2)(x+) and x 2 + x 0(x 2)(x+5) to find their LCD. Their LCD is therefore (x 2)(x+)(x+5). 07

11 x We can then write x 2 x 2 and x+4 as equivalent rational expressions x 2 + x 0 with the same denominator (x 2)(x+)(x+5). x x 2 x 2 x (x 2)(x+) x(x+ 5) (x 2)(x+)(x+ 5) x+4 x 2 + x 0 x+4 (x 2)(x+5) (x+4)(x+) (x 2)(x+5)(x+) Example. Perform the addition or subtraction and simplify. Identify the LCD in each case. (a) 5x 6 + x (b) 8 2a + a (c) 2 2 x 2 x+ Solution. (a) The LCD of the denominators 6 and 8 is 24. Thus 24 is a multiple of both 6 and 8, and we can write and We write both 5x x and as equivalent expressions with the same denominator of 24 and add to 6 8 obtain 5x 6 + x 8 5x x 8 20x x 24 29x 24 Write each term as an equivalent expression with LCD 24 Simplify Add (b) The LCD of the denominators 2a and a 2 is 6a 2. Thus 6a 2 is a multiple of both 2a and a 2, and we can write 6a 2 2a a and 6a 2 a 2 2. We write both 2a and a as equivalent expressions with the same denominator of 2 6a2 and add to obtain 2a + a 2 a 2a a + 2 a 2 2 a 6a a 2 Write each term as an equivalent expression with LCD 6a 2 Simplify a+2 6a 2 Add 08

12 (c) The LCD of the denominators x 2 and x+ is (x 2)(x+). We write 2 both x 2 and as equivalent expressions with the same denominator of x+ (x 2)(x+), subtract and simplify to obtain 2 x 2 x+ 2(x+) (x 2)(x+) (x 2) (x+)(x 2) 2(x+) (x 2) (x 2)(x+) 2x+2 x+6 (x 2)(x+) x+8 (x 2)(x+) Write each term as an equivalent expression with LCD (x 2)(x+) Subtract Expand numerator expressions Collect like terms Example 4. Perform the addition or subtraction and simplify. Identify the LCD in each case. (a) 2y+ (b) y+ x 2 + 4x+4 x+ (c) x 2 4 t 2 t t 2 + 2t Solution. (a) The term 2y is a rational expression with denominator. The LCD of the denominators and y+ is y+. We write both 2y and y+ as equivalent expressions with the same denominator of y+ and add to obtain 2y+ y+ 2y(y+) y+ 2y2 + 2y+ y+ + y+ Write each term as an equivalent expression with LCD y+ Expand 2y(y+) and add (b) We must factor the denominator polynomials x 2 + 4x+4(x+2) 2 and x 2 4 (x 2)(x+ 2) to find their LCD (x+ 2) 2 (x 2). We write both x 2 + 4x+4 and x+ x 2 4 as equivalent expressions with the same denominator of (x+ 2)2 (x 2), subtract and simplify to obtain 09

13 x 2 + 4x+4 x+ x 2 4 (x+2) x+ 2 (x 2)(x+ 2) x 2 (x+2) 2 (x 2) (x+)(x+ 2) (x 2)(x+2)(x+2) Factor denominator polynomials Write each term as an equivalent expression with LCD (x+ 2) 2 (x 2) x 2 (x+)(x+2) Subtract (x 2)(x+2) 2 x 2 (x2 + x+2) (x 2)(x+2) 2 Multiply (x+)(x+2)x 2 +x+2 x2 2x 4 (x 2)(x+2) 2 Collect like terms (c) We factor t 2 + 2tt(t+ 2) and we see that the LCD of the denominators t, t+ 2 and t(t+ 2)is t(t+ 2). We write t, 2 t+ 2 and 4 as equivalent expressions t(t+ 2) with the same denominator of t(t+ 2), subtract and add the numerators, and simplify to obtain t 2 t t 2 + 2t t 2 t t(t+ 2) (t+ 2) t(t+ 2) 2t (t+ 2)t + 4 t(t+ 2) t+ 6 2t+4 t(t+ 2) t+0 t(t+2) Factor t 2 + 2tt(t+ 2) Write each term as an equivalent expression with LCD t(t+ 2) Multiply (t+ 2)t+ 6; subtract and add Collect like terms Exercise Set 5. Suppose the expressions given are denominators of rational expressions. Find their least common denominator (LCD).. x 4 y 5, x 2 y 7 z 2. 2a b 5, a 6 b 2. 2(x ), 9(x ) 4. (x+ 2) (x+ ), (x+ ) 2 (x+4), (x+4) 5 5. x 2 + 5x+6, (x+2) x 2 (y+), 2x(y+) 0

14 7. x 2 25, x 2 +8x+5 8. t(t 2 ),t (t+), t 2 (t ) Write each pair of rational expressions as equivalent rational expressions with their LCD as the denominator for both x 2, 5 x ab 2, a b x 2 y, 8x 5 y x(x ), 7 (x ) 2 x x 2 + 4x+, x+5 x 2 + x+2 2. x+ 4xy, 5y 6x 2 4. x 4x+4, x 2 6. x+ x 2 x 2, 6x x 2 4x+4 Perform the addition or subtraction and simplify. Identify the LCD in each case. 7. y 7x 4 2 7x (x+) (x+) 2 9. x 4 + 2x 2. s + t a + 4 a 2 x 6y 2. c 4 c a 2 b + 2 9ab x + 5 x x r + s + 4t x x+ x x 2 4 x x x 4 5

15 . x x x+7 2. x + 2 x 5 x 2 x. a + a 2 + a 4. x x x 2 + x x x 2 x 2 + 2x 5 x 2 5x+6 x+ 2 (x+) + 2 x x x 2 +x 6 + x+ x 2 + 7x+2 7x x 2 9x+20 x 5 t+ 2t 2 + 5t + t+ 2t 2 t+ 2

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### EAP/GWL Rev. 1/2011 Page 1 of 5. Factoring a polynomial is the process of writing it as the product of two or more polynomial factors. EAP/GWL Rev. 1/2011 Page 1 of 5 Factoring a polynomial is the process of writing it as the product of two or more polynomial factors. Example: Set the factors of a polynomial equation (as opposed to an MTH 092 College Algebra Essex County College Division of Mathematics Sample Review Questions Created January 7, 2006 Math 092, Elementary Algebra, covers the mathematical content listed below. In order Factoring: reversing the distributive property. The distributive property allows us to do the following: When factoring, we look for greatest common factor of each term and reverse the distributive property